We can substitute any value we want for $x$ or any value for $y$. Since the equation is in $y$-form, it will be easier to substitute in values of $x$. Let’s pick $x=0\text{}\text{, }\text{}x=1\text{}\text{, }\text{}x=-1$.

    $x=0$                    $x=1$                    $x=-1$

    $y=9x+2$        $y=9x+2$        $y=9x+2$

Substitute the value into the equation.
    $y=9·0+2$        $y=9·1+2$        $y=9·-1+2$

Simplify.
    $y=0+2$            $y=9+2$                $y=-9+2$

Simplify.
    $y=2$                    $y=11$                        $y=-7$

Write the ordered pair.
    $\left(0\text{, }2\right)$                    $\left(1\text{, }11\right)$                    $\left(-1\text{, }-7\right)$

Check.
$\begin{array}{ccc}(0,2)& (1,11)& (-1,-7)\\ y=9x+2& y=9x+2& y=9x+2\\ 2\text{}\stackrel{?}{=}\text{}9·0+2& 11\text{}\stackrel{?}{=}\text{}9·1+2& -7\text{}\stackrel{?}{=}\text{}9·-1+2\\ 2\text{}\stackrel{?}{=}\text{}0+2& 11\text{}\stackrel{?}{=}\text{}9+2& -7\text{}\stackrel{?}{=}\text{}-9+2\\ 2\text{}=\text{}2\text{}✓& 11\text{}=\text{}11\text{}✓& -7\text{}=\text{}-7\text{}✓\end{array}$

So, $\left(0\text{, }2\right)\text{,}\left(1\text{, }11\right)\text{,}\left(-1\text{, }-7\right)$ are all solutions to $y=9x+2$.