Connectivity of US Counties
Construct the connectivity graph between neighboring US counties.
Take the list of all counties in the contiguous continental US states.
In[1]:=
Length[counties =
Flatten[EntityClass["AdministrativeDivision",
"ContinentalUSStates"]["Subdivisions"]]]
Out[1]=
Add the District of Columbia, which is not a subdivision of any of the 48 contiguous states.
In[2]:=
AppendTo[counties,
Entity["AdministrativeDivision", {"DistrictOfColumbia",
"DistrictOfColumbia", "UnitedStates"}]];
Compute the list of counties bordering each county.
In[3]:=
bordering = EntityValue[counties, "BorderingCounties"];
Discard some cases for which bordering information is not available.
In[4]:=
Length[missingpos = Position[bordering, _Missing]]
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In[5]:=
counties = Delete[counties, missingpos];
bordering = Delete[bordering, missingpos];
Construct the edges of the connectivity graph of the US counties.
In[6]:=
Length[edges =
DeleteDuplicates[
Sort /@ Flatten[
MapThread[Thread[UndirectedEdge[##]] &, {counties, bordering}]]]]
Out[6]=
In[7]:=
Graph[counties, edges]
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To construct a more familiar embedding, download the center position of all counties.
In[8]:=
pos = GeoPosition[EntityValue[counties, "Position"]]
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Use the following cartographic projection.
In[9]:=
proj = {"LambertAzimuthal",
"Centering" ->
Entity["City", {"Topeka", "Kansas", "UnitedStates"}]};
In[10]:=
projpos = First@GeoGridPosition[pos, proj];
Then you have the following graph embedding.
In[11]:=
graph = Graph[counties, edges, VertexCoordinates -> projpos]
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To go from the county of San Francisco to Manhattan, you need to visit at least 67 counties, including the initial and final ones.
In[12]:=
Length[path = FindShortestPath[graph,
Entity[
"AdministrativeDivision", {"SanFranciscoCounty", "California",
"UnitedStates"}],
Entity[
"AdministrativeDivision", {"NewYorkCounty", "NewYork",
"UnitedStates"}]]]
Out[12]=
In[13]:=
HighlightGraph[graph, PathGraph[path]]
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